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x^2+7x-18=180
We move all terms to the left:
x^2+7x-18-(180)=0
We add all the numbers together, and all the variables
x^2+7x-198=0
a = 1; b = 7; c = -198;
Δ = b2-4ac
Δ = 72-4·1·(-198)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-29}{2*1}=\frac{-36}{2} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+29}{2*1}=\frac{22}{2} =11 $
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